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30x-6x^2=12
We move all terms to the left:
30x-6x^2-(12)=0
a = -6; b = 30; c = -12;
Δ = b2-4ac
Δ = 302-4·(-6)·(-12)
Δ = 612
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{612}=\sqrt{36*17}=\sqrt{36}*\sqrt{17}=6\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6\sqrt{17}}{2*-6}=\frac{-30-6\sqrt{17}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6\sqrt{17}}{2*-6}=\frac{-30+6\sqrt{17}}{-12} $
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